(y)(y^2+1)(y-2)=0

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Solution for (y)(y^2+1)(y-2)=0 equation: 


Simplifying
(y)(y2 + 1)(y + -2) = 0

Reorder the terms:
y(1 + y2)(y + -2) = 0

Reorder the terms:
y(1 + y2)(-2 + y) = 0

Multiply (1 + y2) * (-2 + y)
y(1(-2 + y) + y2(-2 + y)) = 0
y((-2 * 1 + y * 1) + y2(-2 + y)) = 0
y((-2 + 1y) + y2(-2 + y)) = 0
y(-2 + 1y + (-2 * y2 + y * y2)) = 0
y(-2 + 1y + (-2y2 + y3)) = 0
y(-2 + 1y + -2y2 + y3) = 0
(-2 * y + 1y * y + -2y2 * y + y3 * y) = 0
(-2y + 1y2 + -2y3 + y4) = 0

Solving
-2y + 1y2 + -2y3 + y4 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), 'y'.
y(-2 + y + -2y2 + y3) = 0


Subproblem 1
Set the factor 'y' equal to zero and attempt to solve:

Simplifying
y = 0

Solving
y = 0

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = 0

Subproblem 2
Set the factor '(-2 + y + -2y2 + y3)' equal to zero and attempt to solve:

Simplifying
-2 + y + -2y2 + y3 = 0

Solving
-2 + y + -2y2 + y3 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Solution
y = {0}

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